时间戳

首页 > 解决方案 > 无法使用 python 从 Json 文件中获取特定值

python - 无法使用 python 从 Json 文件中获取特定值

问题描述

我很难从我的 json 文件中获取一些数据。我能够获得一些数据，但是当我想更详细地挖掘时，我遇到了错误并且卡在了哪里。

运行下面的脚本会返回错误

AttributeError: 'list' object has no attribute 'get'

我知道它是一个列表，但我不确定如何获取对象列表的其余部分。

脚本

ifile=open('source.json', 'r')
ofile=open('extract.json', 'w')
json_decode=json.load(ifile)
myresult=[]
for item in json_decode:
    mydict={}
    mydict['sID']=item.get('Ls id')
    my_dict['dID']=item.get('items').get('Link ID').get('Metric').get('Link Type')
    mydict['type']=item.get('Type')
    myresult.append(mydict)
myjson=json.dumps(myresult, ofile)
ofile.write(myjson)
ofile.close()

源 Json 文件

[
  {
    "Ls age": "201",
    "items": [
      {
        "Link ID": "1.1.1.2",
        "Link Type": "StubNet",
        "Metric": "1",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      },
      {
        "Link ID": "1.1.1.4",
        "Link Type": "P-2-P",
        "Metric": "1",
        "Data": "192.168.100.34"
      },
      {
        "Link ID": "192.168.100.33",
        "Link Type": "StubNet",
        "Metric": "1",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      },
      {
        "Link ID": "1.1.1.1",
        "Link Type": "P-2-P",
        "Metric": "1",
        "Data": "192.168.100.53"
      }
    ],
    "Len": "84",
    "Ls id": "1.1.1.2",
    "Adv rtr": "1.1.1.2",
    "Type": "Router",
    "Link count": "5"
  },
  {
    "Ls age": "1699",
    "seq#": "80008d72",
    "items": [
      {
        "Link ID": "1.1.1.1",
        "Link Type": "StubNet",
        "Metric": "1",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      },
      {
        "Link ID": "1.1.1.1",
        "Link Type": "StubNet",
        "Metric": "12",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      },
      {
        "Link ID": "1.1.1.3",
        "Link Type": "P-2-P",
        "Metric": "10",
        "Data": "192.168.100.26"
      },
      {
        "Link ID": "192.168.100.25",
        "Link Type": "StubNet",
        "Metric": "10",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      },
      {
        "Link ID": "1.1.1.2",
        "Link Type": "P-2-P",
        "Metric": "10",
        "Data": "192.168.100.54"
      },
      {
        "Link ID": "192.168.100.53",
        "Link Type": "StubNet",
        "Metric": "10",
        "Data": "255.255.255.255",
        "Priority": "Medium"
      }
    ],
    "Len": "96",
    "Ls id": "1.1.1.1",
    "chksum": "0x16fc",
    "Adv rtr": "1.1.1.1",
    "Type": "Router",
    "Options": "ASBR  E",
    "Link count": "6"
  }
]

预计结果如下

[
  {
    "type": "Router",
    "sID": "1.1.1.2",
    "dID": "1.1.1.2",
    "LinkType":"StubNet",
    "Metric":"1"
  },
  { 
    "type": "Router",
    "sID": "1.1.1.2", 
    "dID": "1.1.1.4",
    "Link Type": "P-2-P",
    "Metric": "1"
  },
  {
    "type": "Router",
    "sID": "1.1.1.2",
    "dID": "192.168.100.33",
    "LinkType":"StubNet",
    "Metric":"1"   
  },   
  { 
    "type": "Router",     
    "sID": "1.1.1.2",     
    "dID":"1.1.1.1",
    "Link Type": "P-2-P",
    "Metric": "1"
  },
  {
    "type": "Router",
    "sID": "1.1.1.1",
    "dID": "1.1.1.1",     
    "LinkType":"StubNet",     
    "Metric":"1"  
   },   
   {     
    "type": "Router",
    "sID": "1.1.1.1",
    "dID":"1.1.1.1",
    "Link Type": "StubNet",
    "Metric": "12"
  },
  {
    "type": "Router",
    "sID": "1.1.1.1",
    "dID": "1.1.1.3",
    "LinkType":"P-2-P",
    "Metric":"10"   
  } 
]

感谢建议如何进一步进行。我四处搜索并尝试错误，但仍然无法解决它。感谢您的建议和支持。谢谢

标签： pythonjsonlistextract

解决方案

您应该能够像字典一样访问值，例如：

ifile=open('source.json', 'r')
ofile=open('extract.json', 'w')
json_decode=json.load(ifile)
myresult=[]
for item in json_decode:
    mydict={}
    mydict['sID']=item['Ls id']
    my_dict['dID']=item['items']['Link ID']['Metric']['Link Type']
    mydict['type']=item['Type']
    myresult.append(mydict)
myjson=json.dumps(myresult, ofile)
ofile.write(myjson)
ofile.close()

这对你有用吗？如果没有，您遇到了什么错误？

推荐阅读