javascript - 使用其他数组对对象数组进行排序

Question

我创建了这个对象数组：

const palette = [
  {
    color: 'Blue',
    brightness: 'Soft',
  },
  {
    color: 'Blue',
    brightness: 'Medium',
  },
  {
    color: 'Blue',
    brightness: 'Principal',
  },
  {
    color: 'Magenta',
    brightness: 'Soft',
  },
  {
    color: 'Magenta',
    brightness: 'Medium',
  },
  {
    color: 'Magenta',
    brightness: 'Principal',
  }
]

我想要一个按以下顺序包含对象的新数组：

const colorOrder = ['Blue', 'Magenta']
const brightnessOrder = ['Principal', 'Soft', 'Medium']

所以这是我想要的结果：

const colors = [
  {
    color: 'Blue',
    brightness: 'Principal',
  },
  {
    color: 'Blue',
    brightness: 'Soft',
  },
  {
    color: 'Blue',
    brightness: 'Medium',
  },
  {
    color: 'Magenta',
    brightness: 'Principal',
  }
  {
    color: 'Magenta',
    brightness: 'Soft',
  },
  {
    color: 'Magenta',
    brightness: 'Medium',
  },
]

我试试这个功能：

function sortArrayByAnotherArray(array: any[], order: number[] | string[], key: string) {
  const newArray = array.slice(0).sort((a, b) => {
    const A = a[key]
    const B = b[key]
    return order.indexOf(A) < order.indexOf(B) ? 1 : -1
  })
  return newArray
}

我这样称呼它：

const palette1 = sortArrayByAnotherArray(
  palette,
  brightnessOrder,
  'brightness'
)
const palette2 = sortArrayByAnotherArray(
  palette1,
  colorOrder,
  'color'
)

console.log('\n', palette)

console.log('\n', brightnessOrder)
console.log(palette1)

console.log('\n', colorOrder)
console.log(palette2)

结果是：

`
` [ { color: 'Blue', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Principal' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Principal' } ]
`
` [ 'Principal', 'Soft', 'Medium' ]
[ { color: 'Blue', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Principal' },
  { color: 'Magenta', brightness: 'Principal' } ]
`
` [ 'Blue', 'Magenta' ]
[ { color: 'Magenta', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Principal' },
  { color: 'Blue', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Principal' } ]

这是一团糟，顺序不像数组中的顺序：颜色是反转的，亮度值也是反转的。然后我认为调用这个函数两次（或更多）会产生问题。有没有办法解决这个问题？是否存在一种聪明的方式来做我需要的事情？

标签： javascriptsorting

Answer 1

您可以将所需的顺序与逻辑 OR||和索引的增量链接起来。

const
    palette = [{ color: 'Blue', brightness: 'Soft' }, { color: 'Blue', brightness: 'Medium' }, { color: 'Blue', brightness: 'Principal' }, { color: 'Magenta', brightness: 'Soft' }, { color: 'Magenta', brightness: 'Medium' }, { color: 'Magenta', brightness: 'Principal' }],
    colorOrder = ['Blue', 'Magenta'],
    brightnessOrder = ['Principal', 'Soft', 'Medium'];

palette.sort((a, b) => 
    colorOrder.indexOf(a.color) - colorOrder.indexOf(b.color) ||
    brightnessOrder.indexOf(a.brightness) - brightnessOrder.indexOf(b.brightness)
);

console.log(palette);

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一种使用函数和给定顺序数组对副本进行排序的方法。

function sortArrayByAnotherArrays(data, orders) {
    const
        getObject = array => array.reduce((r, k, i) => (r[k] = i + 1, r), {}),
        objects = orders.map(([k, a]) => [k, getObject(a)]);

    return data
        .slice()
        .sort((a, b) => {
            var v;
            objects.some(([k, o]) => v = o[a[k]] - o[b[k]]);
            return v;
        });
}

const
    palette = [{ color: 'Blue', brightness: 'Soft' }, { color: 'Blue', brightness: 'Medium' }, { color: 'Blue', brightness: 'Principal' }, { color: 'Magenta', brightness: 'Soft' }, { color: 'Magenta', brightness: 'Medium' }, { color: 'Magenta', brightness: 'Principal' }],
    colorOrder = ['Blue', 'Magenta'],
    brightnessOrder = ['Principal', 'Soft', 'Medium'],
    ordered = sortArrayByAnotherArrays(
        palette,
        [
            ['color', colorOrder],           // [key, values in order]
            ['brightness', brightnessOrder]
        ]
    );

console.log(ordered);

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