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python - 使用 .loc 和 OR 运算符返回 ValueError

问题描述

我正在尝试在两列中的任何一列中搜索特定值，当找到目标值时，将第三列中的数字从正数更改为负数或从负数更改为正数。

te1 = df.loc[df['Transaction Event'] == 'Exercise']
te2 = df.loc[df['Transaction Event'] == 'Assignment']
te3 = df.loc[df['Transaction Event'] == 'Expiration']
an1 = df.loc[df['Action'] == 'Delete']
nq = df['Net Quantity']
var1 = df[(df['Transaction Event'] == 'Exercise') | (df['Transaction Event'] == 'Assignment') | (df['Transaction Event'] == 'Expiration') | (df['Action'] == 'Delete')]

df.loc[df[var1], nq] = df.loc[df[var1], nq] * -1

运行此代码会返回以下错误：

---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-282-01dbb8066276> in <module>()
      6 var1 = df[(df['Transaction Event'] == 'Exercise') | (df['Transaction Event'] == 'Assignment') | (df['Transaction Event'] == 'Expiration') | (df['Action'] == 'Delete')]
      7 
----> 8 df.loc[df[var1], nq] = df.loc[df[var1], nq] * -1
      9 print(df)

C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\frame.py in __getitem__(self, key)
   1958             return self._getitem_array(key)
   1959         elif isinstance(key, DataFrame):
-> 1960             return self._getitem_frame(key)
   1961         elif is_mi_columns:
   1962             return self._getitem_multilevel(key)

C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\frame.py in _getitem_frame(self, key)
   2034         if key.values.size and not is_bool_dtype(key.values):
   2035             raise ValueError('Must pass DataFrame with boolean values only')
-> 2036         return self.where(key)
   2037 
   2038     def query(self, expr, inplace=False, **kwargs):

C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\generic.py in where(self, cond, other, inplace, axis, level, try_cast, raise_on_error)
   5338         other = com._apply_if_callable(other, self)
   5339         return self._where(cond, other, inplace, axis, level, try_cast,
-> 5340                            raise_on_error)
   5341 
   5342     @Appender(_shared_docs['where'] % dict(_shared_doc_kwargs, cond="False",

C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\generic.py in _where(self, cond, other, inplace, axis, level, try_cast, raise_on_error)
   5096             for dt in cond.dtypes:
   5097                 if not is_bool_dtype(dt):
-> 5098                     raise ValueError(msg.format(dtype=dt))
   5099 
   5100         cond = cond.astype(bool, copy=False)

ValueError: Boolean array expected for the condition, not float64

有谁知道是什么导致了这个错误？

标签： pythonoperatorsvalueerror

解决方案

您不是在创建掩码，而是在df执行此操作时选择了掩码的一个子集：

var1 = df[(df['Transaction Event'] == 'Exercise') | (df['Transaction Event'] == 'Assignment') | (df['Transaction Event'] == 'Expiration') | (df['Action'] == 'Delete')]

相反，您只需要这个：

var1 = (df['Transaction Event'] == 'Exercise') | (df['Transaction Event'] == 'Assignment') | (df['Transaction Event'] == 'Expiration') | (df['Action'] == 'Delete')

在您当前的代码中，您创建所需的布尔数组，但还df使用该数组另外索引到您的原始数组。var1您可以确认您是否查看了当前代码中实际包含的内容。

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