python - df.apply(lambda: x.lower()): 'function' 对象没有属性 'lower'

Question

我在 Jupyter 中编写了这段代码，但收到一条错误消息：

tokenizer = RegexpTokenizer (r'\w+')

career_df['How could the conversation have been more useful?']= career_df['How could the conversation have been more useful?'].apply(lambda x:tokenizer.tokenize(x.lower()))

错误是

AttributeError：'function'对象没有属性'lower'

标签： pythondataframestringtokenizer

Answer 1

lambda 表达式中的“x”在应该是字符串时充当函数。尝试 ：

  career_df['How could the conversation have been more useful?']= career_df.apply(lambda x:tokenizer.tokenize(x['How could the conversation have been more useful?'].lower()))