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python - 如何在忽略索引列值的现有 Excel 工作表下方写入数据框？

问题描述

我在现有的 excel 文件下面附加了一个数据框。借助以下代码，数据框已成功附加到 Excel 文件下方，但数据框的索引值显示为我的第一列，即 A 列。

例如 -

1.我现有的excel文件如下-

   A         B         C                                                                
  10        20        30
  30        40        50

  1. 我的数据框遵循 df1-

    a = {'A':[10,11,12],'B':[12,13,14],'C':[14,15,16]} df1 = pd.DataFrame(a) #Dataframe to附加在现有 Excel 文件下方

3.运行代码后，我得到以下输出-

   A         B         C     D 
  10        20        30
  30        40        50
   0        10        11    12
   1        12        13    14
   2        14        15    16

4.但我希望输出如下（期望的输出）

   A         B         C   
  10        20        30
  30        40        50
  10        11        12    
  12        13        14    
  14        15        16

5. 步骤 3 中显示的输出包括索引值 0,1 和 2，但我不想要该索引值。相反，我希望 A 列必须附加在 A 列下方，B 列在 B 列下方，C 列在 C 列下方。

简而言之，我不希望索引值出现在我的 excel 文件中，因为我使用索引值得到了错误的 Excel 文件。

由于我的数据框中存在索引值，我的数据框数据正在向右移动一列。

我的代码是

#Below is a method to write dataframe value below an existing excel file
    def append_df_to_excel(filename, df, sheet_name='Sheet1', startrow=None        [truncate_sheet][1]=False,
                           **to_excel_kwargs):
        """
        Append a DataFrame [df] to existing Excel file [filename]
        into [sheet_name] Sheet.
        If [filename] doesn't exist, then this function will create it.

        Parameters:
          filename : File path or existing ExcelWriter
                     (Example: '/path/to/file.xlsx')
          df : dataframe to save to workbook
          sheet_name : Name of sheet which will contain DataFrame.
                       (default: 'Sheet1')
          startrow : upper left cell row to dump data frame.
                     Per default (startrow=None) calculate the last row
                     in the existing DF and write to the next row...
          truncate_sheet : truncate (remove and recreate) [sheet_name]
                           before writing DataFrame to Excel file
          to_excel_kwargs : arguments which will be passed to `DataFrame.to_excel()`
                            [can be dictionary]

        Returns: None
        """
        from openpyxl import load_workbook

        import pandas as pd

        # ignore [engine] parameter if it was passed
        if 'engine' in to_excel_kwargs:
            to_excel_kwargs.pop('engine')

        writer = pd.ExcelWriter(filename, engine='openpyxl')

        # Python 2.x: define [FileNotFoundError] exception if it doesn't exist
        try:
            FileNotFoundError
        except NameError:
            FileNotFoundError = IOError


        try:
            # try to open an existing workbook
            writer.book = load_workbook(filename)

            # get the last row in the existing Excel sheet
            # if it was not specified explicitly
            if startrow is None and sheet_name in writer.book.sheetnames:
                startrow = writer.book[sheet_name].max_row

            # truncate sheet
            if truncate_sheet and sheet_name in writer.book.sheetnames:
                # index of [sheet_name] sheet
                idx = writer.book.sheetnames.index(sheet_name)
                # remove [sheet_name]
                writer.book.remove(writer.book.worksheets[idx])
                # create an empty sheet [sheet_name] using old index
                writer.book.create_sheet(sheet_name, idx)

            # copy existing sheets
            writer.sheets = {ws.title:ws for ws in writer.book.worksheets}
        except FileNotFoundError:
            # file does not exist yet, we will create it
            pass

        if startrow is None:
            startrow = 1

        # write out the new sheet
        df.to_excel(writer, sheet_name, startrow=startrow, **to_excel_kwargs)

        # save the workbook
        writer.save()

    import pandas as pd
    a = {'A':[10,11],'B':[12,13],'C':[14,15]}
    df1 = pd.DataFrame(a)          #df1 is datafame which I want to append
    path1 = r"C:\Users\Desktop\ab.xlsx"    #PATH OF EXISTING EXCEL FILE 
    append_df_to_excel(path1, df1, sheet_name='Sheet1')

标签： pythonpandasopenpyxl

解决方案

根据文档，如果您不想编写行名，请将索引参数设置为 false。

IE

df.to_excel(writer, sheet_name, startrow=startrow, **to_excel_kwargs)

应该

df.to_excel(writer, sheet_name, startrow=startrow, , index=False, **to_excel_kwargs)

在您的代码的完整上下文中（带有一些内务处理）：

import pandas as pd
from openpyxl import load_workbook


def append_df_to_excel(filename, df, sheet_name='Sheet1', startrow=1, truncate_sheet=False, **to_excel_kwargs):

    # ignore [engine] parameter if it was passed
    if 'engine' in to_excel_kwargs:
        to_excel_kwargs.pop('engine')

    writer = pd.ExcelWriter(filename, engine='openpyxl')

    try:
        # try to open an existing workbook
        writer.book = load_workbook(filename)

        # get the last row in the existing Excel sheet
        # if it was not specified explicitly
        if startrow is None and sheet_name in writer.book.sheetnames:
            startrow = writer.book[sheet_name].max_row

        # truncate sheet
        if truncate_sheet and sheet_name in writer.book.sheetnames:
            # index of [sheet_name] sheet
            idx = writer.book.sheetnames.index(sheet_name)
            # remove [sheet_name]
            writer.book.remove(writer.book.worksheets[idx])
            # create an empty sheet [sheet_name] using old index
            writer.book.create_sheet(sheet_name, idx)

        # copy existing sheets
        writer.sheets = {ws.title: ws for ws in writer.book.worksheets}

    except FileNotFoundError:
        # file does not exist yet, we will create it
        pass

    if startrow is None:
        startrow = 1

    # write out the new sheet
    df.to_excel(writer, sheet_name, startrow=startrow, index=False, **to_excel_kwargs)

    # save the workbook
    writer.save()


if __name__ == '__main__':
    a = {'A': [10, 11], 'B': [12, 13], 'C': [14, 15]}
    df1 = pd.DataFrame(a)  # df1 is datafame which I want to append
    path1 = r"C:\Users\Desktop\ab.xlsx"  # PATH OF EXISTING EXCEL FILE
    append_df_to_excel(path1, df1, sheet_name='Sheet1')

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