ansible - Ansible 在标准输出输出中搜索子字符串
问题描述
团队,我正在尝试匹配一个版本,但当整个字符串不匹配时会失败。所以我只想匹配前两个八位字节。我尝试了几个组合,但没有运气。
- name: "Validate k8s version"
shell: "kubectl version --short"
register: k8s_version_live
failed_when: k8s_version_live.stdout_lines is not search("{{ k8s_server_version }}")
#failed_when: "'{{ k8s_server_version }}' not in k8s_version_live.stdout_lines"
ignore_errors: yes
- debug:
var: k8s_version_live.stdout_lines
输出:
[WARNING]: conditional statements should not include jinja2 templating delimiters such as {{ }} or {% %}. Found: k8s_version_live.stdout_lines is not search("{{
k8s_server_version }}")
fatal: [localhost]: FAILED! => {"changed": true, "cmd": "kubectl version --short", "delta": "0:00:00.418128", "end": "2019-12-05 02:13:15.108997", "failed_when_result": true, "rc": 0, "start": "2019-12-05 02:13:14.690869", "stderr": "", "stderr_lines": [], "stdout": "Client Version: v1.13.3\nServer Version: v1.13.10", "stdout_lines": ["Client Version: v1.13.3", "Server Version: v1.13.10"]}
...ignoring
TASK [team-services-pre-install-checks : debug] *************************************************************************************************************************
Thursday 05 December 2019 02:13:15 +0000 (0:00:00.902) 0:00:01.039 *****
ok: [localhost] => {
"k8s_version_live.stdout_lines": [
"Client Version: v1.13.3",
"Server Version: v1.13.10"
]
}```
解决方案
问:“匹配一个版本...匹配前两个八位字节”
A:使用版本比较。例如,从注册的输出创建变量k8s_server_version
- set_fact:
k8s_server_version: "{{ k8s_version_live.stdout_lines.1.split(':').1[2:] }}"
比较版本的前两个数字
- debug:
msg: "{{ k8s_server_version }} match 1.13"
when:
- k8s_server_version is version('1.13', '>=')
- k8s_server_version is version('1.14', '<')
给
}
localhost | SUCCESS => {
"msg": "1.13.10 match 1.13"
}
版本不匹配失败
- fail:
msg: "{{ k8s_server_version }} does not match 1.12"
when: not (k8s_server_version is version('1.12', '>=') and
k8s_server_version is version('1.13', '<'))
给
localhost | FAILED! => {
"changed": false,
"msg": "1.13.10 does not match 1.12"
}