python - 使用 Python 2.7，我如何修复此代码，以便程序在工作日将每个结果乘以 64，在周末将每个结果乘以 80？

Question

• 这是我的代码：

  days=["Sunday: ", "Monday: ", "Tuesday: ", "Wednesday: ", "Thursday: ", "Friday: ", "Saturday: "]
  Wdays=["Monday: ", "Tuesday: ", "Wednesday: ", "Thursday: ", "Friday: "]
  Wends=["Sunday: ", "Saturday: "]
  demand=[]
  temp=[]
  demand=[15, 20, 25, 18, 20, 22, 14]
  while demand[0]>0 or demand[1]>0 or demand[2]>0 or demand[3]>0 or demand[4]>0 or demand[5]>0 or demand[6]>0:
      min1=min(demand)
      ind1=demand.index(min1)
      temp=demand.copy()
      temp[ind1]=100000
      min2=min(temp)
      ind2=temp.index(min2)
      for i in range(7):
          if i != ind1 and i != ind2:
              demand[i]-=1
      print(demand)
  for e in range(7):
      while demand[e]:
          if Wdays:
              demand[e]-=1*64
          else:
              demand[e]-=1*80
  print(demand[e])`
  

• 代码的第二部分似乎有错误：

  for e in range(7):
      while demand[e]:
          if Wdays:
              demand[e]-=1*64
          else:
              demand[e]-=1*80
  print(demand[e])
  

• 但是我找不到它。目标是输出这个，例如：

  [15, 19, 24, 17, 19, 21, 14]
  Weekdays: $6400
  Weekends: $2320
  

• 它将（1到5）中的数字相加并将它们乘以64，然后将（0和6）中的数字相加并将它们乘以

标签： pythonpython-2.7