shell - Shell：在字母数字字符后添加换行符

Question

我需要在以下段落中的字母数字字符（例如：11.34s）之后添加一个换行符 - 在 Shell 中

输入：

zip_upload : Unzipping the new release at /path - 338.17s Gathering Facts --------------------------------------------------------- 4.78s zip_upload : Upload the zipped binaries to repository ---------- 2.48s zip_upload : Find the file applicatons.yml in remote node ------ 1.87s zip_upload : Upload to repository ---------------------- 0.92s zip_upload : include_tasks ------------------------------------------- 0.71s

需要的输出如下：

zip_upload : Unzipping the new release at /path - 338.17s
Gathering Facts --------------------------------------------------------- 4.78s
zip_upload : Upload the zipped binaries to repository ---------- 2.48s
zip_upload : Find the file applicatons.yml in remote node ------ 1.87s
zip_upload : Upload to repository ---------------------- 0.92s
zip_upload : include_tasks ------------------------------------------- 0.71s 

请帮忙

标签： shellsed

Answer 1

单程：

sed -r "s/([0-9]\.[0-9][0-9]s) /&\n/g" file

这个 sed 寻找一个模式[digit].[digit][digit]s，然后用模式匹配（&）替换，然后是换行（\n）。