python-3.x - 为什么我们使用 hadoop mapreduce 进行数据处理?为什么不在本地机器上做呢?
问题描述
我很困惑,我尝试像一百万个随机数一样采用概率。我尝试在谷歌 dataProc 中使用 MapReduce 两种方法,并在 spyder 上运行 python 脚本来做同样的事情。但更快的是本地机器。那我们为什么要使用 Mapreduce 呢?我使用以下代码。
#!/usr/bin/env python3
import timeit
start = timeit.default_timer()
from collections import Counter
import numpy as np
import matplotlib.pyplot as plt
#Random Number Generating
x = np.random.randint(low=1, high=100, size=1000000)
counts = Counter(x)
total = sum(counts.values())
d1 = {k:v/total for k,v in counts.items()}
grad = d1.keys()
prob = d1.values()
#print(str(grad))
#print(str(prob))
#bins = 20
plt.hist(prob,bins=20, normed=1, facecolor='blue', alpha=0.5)
#plt.plot(bins, hist, 'r--')
plt.xlabel('Probability')
plt.ylabel('Number Of Students')
plt.title('Histogram of Students Grade')
plt.subplots_adjust(left=0.15)
plt.show()
stop = timeit.default_timer()
print('Time: ', stop - start)
#!/usr/bin/env python3
"""mapper.py"""
import sys
# Get input lines from stdin
for line in sys.stdin:
# Remove spaces from beginning and end of the line
#line = line.strip()
# Split it into tokens
#tokens = line.split()
#Get probability_mass values
for probability_mass in line:
print("None\t{}".format(probability_mass))
#print(str(probability_mass)+ '\t1')
#print('%s\t%s' % (probability_mass, None))
#!/usr/bin/env python3
"""reducer.py"""
import sys
from collections import defaultdict
counts = defaultdict(float)
# Get input from stdin
for line in sys.stdin:
#Remove spaces from beginning and end of the line
#line = line.strip()
# skip empty lines
if not line:
continue
# parse the input from mapper.py
k,v = line.split('\t', 1)
counts[v] += 1
total = (float(sum(counts.values())))
#total = sum(counts.values())
probability_mass = {k:v/total for k,v in counts.items()}
print(probability_mass)
解决方案
Hadoop用于存储和处理大数据。在 Hadoop 中,数据存储在作为集群运行的廉价商品服务器上。它是一个分布式文件系统,允许并发处理和容错。Hadoop MapReduce 编程模型用于更快地从其节点存储和检索数据。
Google Dataproc 是云端的 Apache Hadoop。当体积很大时,单台机器不足以处理 Map/Reduce。100万是小体积。