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python - 如何通过舍入结果来规范化数组（python、numpy、scipy）

问题描述

进一步不是正确的代码。如何让它正确、简短、美观？

def normalize_weights(weights, threshold=0.01):
    total = sum(weights)
    result = [x / total for x in weights]
    result = [int((1.0 / threshold) * x) * threshold for x in result]
    result[-1] = 1.0 - sum(result[:-1])
    print(result)
    result[-1] = int((1.0 / threshold) * result[-1]) * threshold
    print(result)

normalize_weights([1.0, 1.0, 1.0])
[0.33, 0.33, 0.33999999999999997]
[0.33, 0.33, 0.34]  # ok

normalize_weights([1.0, 3.0, 1.0])
[0.2, 0.6, 0.19999999999999996]
[0.2, 0.6, 0.19]  # wrong

提前致谢

编辑：结果的总和应该等于 1.0

标签： pythonnumpynormalize

解决方案

a = numpy.array([1.0,3.0,1.0])
normalized_a = numpy.round(a/numpy.linalg.norm(a,1.0),2)
# [0.2,0.6,0.2]

也许？

a = numpy.array([1.0,1.0,1.0])
normalized_a = numpy.round(a/numpy.linalg.norm(a,1.0),2)
# [0.33,0.33,0.33]

如果你想有 2 位小数并强制1.0修复它

normalized_a[0] += 1.0 - numpy.sum(normalized_a) # we could just as easily fix the -1 index ...

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