python - 如何根据列表中的字符串匹配文本并在 Python 中提取小节？

Question

我正在尝试从类似于以下示例的收益调用文本生成结构：

"Operator

Ladies and gentlemen, thank you for standing by. And welcome to XYZ Fourth Quarter 2019 Earning Conference Call. At this time, all participants are in a listen-only mode. After the speaker presentation, there will be a question-and-answer session. [Operator Instructions] Please be advised that today’s conference is being recorded. [Operator Instructions]
I would now like to hand the conference to your speaker today,Person1, Head of Investor Relations. Please go ahead, ma’am**

Person1

Hello everyone, blablablablabla. Now let's see what Person2 has to say.

Person2

Thank you and hello everyone. Blablablabla

Person3

I have no further remarks....thank you once again"

由此我生成了一个名为list1 = ['Person1','Person2','Person3']. 我生成了一个空数据框，其列名称为Person1,Person2和Person3. 我现在必须提取下面的文本Person1，Person2并Person3根据列表中的值并填写数据框。那可能吗？

标签： pythonregexnlp

Answer 1

text="""OperatorLadies and gentlemen, thank you for standing by. And welcome to XYZ Fourth Quarter 2019 Earning Conference Call. At this time, all participants are in a listen-only mode. After the speaker presentation, there will be a question-and-answer session. [Operator Instructions] Please be advised that today’s conference is being recorded. [Operator Instructions]I would now like to hand the conference to your speaker today,Person1, Head of Investor Relations. Please go ahead, ma’am**Person1Hello everyone, blablablablabla. Now let's see what Person2 has to say.Person2Thank you and hello everyone. BlablablablaPerson3I have no further remarks....thank you once again"""

import re
say1=text.split('Person1')[2].split('Person2')[0] #getting text of person1
say2=text.split('Person2')[2].split('Person3')[0] #getting text of person2
say3=text.split('Person3')[1] #getting text of person3

#converting to a dataframe
pd.DataFrame({'Person1':say1,'Person2':say2,'Person3':say3},index=[1])