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问题描述

我有两个班,UserAddress。一个用户可以有多个地址和一个默认地址。我试过这个 SQLAlchemy 代码。

from sqlalchemy import create_engine
from sqlalchemy import Column, Integer, String
from sqlalchemy import ForeignKey

from sqlalchemy.ext.declarative import declarative_base

from sqlalchemy.orm import sessionmaker, relationship


engine = create_engine('sqlite:///:memory:', echo=True)

Base = declarative_base()


class User(Base):
    __tablename__ = 'users'

    id = Column(Integer, primary_key=True)
    default_address_id = Column(Integer, ForeignKey('addresses.id'))
    name = Column(String)
    fullname = Column(String)
    nickname = Column(String)

    addresses = relationship("Address", order_by="Address.id", back_populates="user")


class Address(Base):
    __tablename__ = 'addresses'
    id = Column(Integer, primary_key=True)
    email_address = Column(String, nullable=False)
    user_id = Column(Integer, ForeignKey('users.id'))

    user = relationship("User", back_populates="addresses")


Base.metadata.create_all(engine)

它导致错误

sqlalchemy.exc.AmbiguousForeignKeysError: Could not determine join condition between parent/child tables on relationship User.addresses - there are multiple foreign key paths linking the tables.  Specify the 'foreign_keys' argument, providing a list of those columns which should be counted as containing a foreign key reference to the parent table.

我试图增加foreign_keys这种关系,但我无法做到正确。

标签: pythonsqlalchemy

解决方案


这不是正确的方法,您应该从用户表的 default_adderess_id 中删除外键。如果您想在默认地址和其他地址之间有所不同,您可以在地址表中再添加一个字段作为类型


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