Currently i have this json:

{
    "ResponseCode":200,
     "data":[
       "2016-08-05T15:49:15.157000+00:00",
       "SomeString",
        1230,
        9.025
    ]
}

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首页  > 解决方案 > 解析 Json 列表 to a concrete model In C#

Currently i have this json:



{
    "ResponseCode":200,
     "data":[
       "2016-08-05T15:49:15.157000+00:00",
       "SomeString",
        1230,
        9.025
    ]
}














c# - 解析 Json 列表 to a concrete model In C#

Currently i have this json:



{
    "ResponseCode":200,
     "data":[
       "2016-08-05T15:49:15.157000+00:00",
       "SomeString",
        1230,
        9.025
    ]
}







问题描述



Currently i have this json:



{
    "ResponseCode":200,
     "data":[
       "2016-08-05T15:49:15.157000+00:00",
       "SomeString",
        1230,
        9.025
    ]
}





I can deserialize json string to this



public class Example1
{
    public int ResponseCode { get; set; }
    public IList<object> data { get; set; }
}




But i would like to deserialize “data” to a concrete model instead of 
IList<object>



public class Example1
{
    public int ResponseCode { get; set; }

    public DataModel data { get; set; }
}

public class DataModel
{

    public DateTime date { get; set; }

    public string SomeString { get; set; }

       ...

}




Im using System.Text.Json nuget package.
What should i do? Can i solve this with a custom implementation of JsonConvert<T>?









Please use to install:



dnf install -y iproute-tc




https://centos.pkgs.org/8/centos-baseos-x86_64/iproute-tc-4.18.0-15.el8.x86_64.rpm.html


标签： c#jsondeserializationsystem.text.json


解决方案









如果你想使用 DataModel 类，你需要更新你的 json 值：



{
    "ResponseCode":200,
     "data": {
       "date": "2016-08-05T15:49:15.157000+00:00",
       "someString": "SomeString",
       "anotherVal": 1230,
       "anotherVal2": 9.025
    }
}




其中 data 是 Example1.data 参数，“date”、“someString”、“anotherVal”和“anotherVal2”是 DataModel 参数










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