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python - 使用包含查询字符串的请求下载图像

问题描述

我正在尝试从 Instagram 媒体 URL 下载图像： https ://instagram.fybz2-1.fna.fbcdn.net/v/t51.2885-15/fr/e15/p1080x1080/106602453_613520712600632_6255422472318530180_n.jpg?_nc_ht= .fybz2-1.fna.fbcdn.net&_nc_cat=108&_nc_ohc=WQizf6rhDmQAX883HrQ&oh=140f221889178fd03bf654cf18a9d9a2&oe=5F4D2AFE

将其粘贴到我的浏览器中会显示图像，但是当我运行以下代码时，我收到以下错误，我怀疑这是由于包含查询字符串的 URL 的问题（在以 .j​​pg 结尾的简单 url 上运行它没有问题

  File "C:/Users/19053/InstagramImageDownloader/downloadImage.py", line 18, in <module>
    with open(filename, 'wb') as f:
OSError: [Errno 22] Invalid argument: '106602453_613520712600632_6255422472318530180_n.jpg?_nc_ht=instagram.fybz2-1.fna.fbcdn.net&_nc_cat=108&_nc_ohc=WQizf6rhDmQAX883HrQ&oh=140f221889178fd03bf654cf18a9d9a2&oe=5F4D2AFE'

完整代码如下：

## Importing Necessary Modules
import requests  # to get image from the web
import shutil  # to save it locally

## Set up the image URL and filename
image_url = "https://instagram.fybz2-1.fna.fbcdn.net/v/t51.2885-15/fr/e15/p1080x1080/106602453_613520712600632_6255422472318530180_n.jpg?_nc_ht=instagram.fybz2-1.fna.fbcdn.net&_nc_cat=108&_nc_ohc=WQizf6rhDmQAX883HrQ&oh=140f221889178fd03bf654cf18a9d9a2&oe=5F4D2AFE"
filename = image_url.split("/")[-1]

# Open the url image, set stream to True, this will return the stream content.
r = requests.get(image_url, stream=True)

# Check if the image was retrieved successfully
if r.status_code == 200:
    # Set decode_content value to True, otherwise the downloaded image file's size will be zero.
    r.raw.decode_content = True

    # Open a local file with wb ( write binary ) permission.
    with open(filename, 'wb') as f:
        shutil.copyfileobj(r.raw, f)

    print('Image sucessfully Downloaded: ', filename)
else:
    print('Image Couldn\'t be retreived')

标签： pythonimageurlpython-requestsinstagram

解决方案

问题出在文件名上。您需要先拆分，?然后取第一个元素，然后拆分/

import requests  # to get image from the web
import shutil  # to save it locally

## Set up the image URL and filename
image_url = "https://instagram.fybz2-1.fna.fbcdn.net/v/t51.2885-15/fr/e15/p1080x1080/106602453_613520712600632_6255422472318530180_n.jpg?_nc_ht=instagram.fybz2-1.fna.fbcdn.net&_nc_cat=108&_nc_ohc=WQizf6rhDmQAX883HrQ&oh=140f221889178fd03bf654cf18a9d9a2&oe=5F4D2AFE"
filename = image_url.split("?")[0].split("/")[-1]

# Open the url image, set stream to True, this will return the stream content.
r = requests.get(image_url, stream=True)

# Check if the image was retrieved successfully
if r.status_code == 200:
    # Set decode_content value to True, otherwise the downloaded image file's size will be zero.
    r.raw.decode_content = True

    # Open a local file with wb ( write binary ) permission.
    with open(filename, 'wb') as f:
        shutil.copyfileobj(r.raw, f)

    print('Image sucessfully Downloaded: ', filename)
else:
    print('Image Couldn\'t be retreived')

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