go - 向 gorilla websocket 连接发送任意 JSON

Question

我有以下功能，我想将任意 JSON 数据发送到 websocket 连接。数据取决于发送到服务器的内容。如果不为我要发送的每件东西创建不同的结构，如何实现这一点？

我正在考虑这样的事情：

func Register(c *websocket.Conn, m WebsocketGeneralClientMessage) {
    var d RegisterData
    json.Unmarshal(m.Data, &d)
    if len(d.Email) < 6 || len(d.Email) > 64 {
        c.WriteJSON(WebsocketGeneralServerMessage{
            Type: "error", Data: map[string]interface{"text": "This is an error"}})
        return
    }
    if len(d.Password) < 6 || len(d.Password) > 32 {
        c.WriteJSON(WebsocketGeneralServerMessage{
            Type: "error", Data: map[string]interface{"text": "This is another error"}})
        return
    }
    err := checkmail.ValidateFormat(d.Email)
    if err != nil {
        c.WriteJSON(WebsocketGeneralServerMessage{
            Type: "error", Data: map[string]interface{"text": "This is different than all the previous errors"}})
        return
    }
    uuid, email, password, err := DB.RegisterAccount(requestEmail, requestPassword)
    if err != nil {
        c.WriteJSON(WebsocketGeneralServerMessage{
            Type: "error", Data: map[string]interface{"text": "An error occured while saving the account to the database"}})
        return
    }
    c.WriteJSON(WebsocketGeneralServerMessage{
        Type: "success", Data: map[string]interface{"uuid": uuid}})
    return
}

type WebsocketGeneralServerMessage struct {
    Type string
    Data map[string]interface{}
}

但是，编译器说：

syntax error: unexpected literal "text", expecting method or interface name

所以看起来这个语法是无效的。在这里可以做什么？

标签： gogorilla

Answer 1

是map[string]interface{}{"text": ...。你错过了{}.