apache-spark - 无法从 Spark 查询外部 Hive 表
问题描述
我有一个 Hive 外部表作为 TEXTFILE FORMAT
hive> SHOW CRAETE TABLE customers;
CREATE EXTERNAL TABLE `customers`(
`id` int,
`name` string,
`age` int,
`address` string,
`salary` double)
COMMENT 'Customer Details'
ROW FORMAT SERDE 'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
WITH SERDEPROPERTIES ('field.delim'=',','line.delim'='\n','serialization.format'=',')
STORED AS INPUTFORMAT 'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT 'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION 'hdfs://localhost:9000/user/hive/warehouse/shopping.db/customers'
TBLPROPERTIES ('skip.header.line.count'='1','transient_lastDdlTime'='1605818870')
和火花会话如下:
val warehouseLocation:String = "hdfs://localhost:9000/user/hive/warehouse/"
val spark = SparkSession.builder()
.appName("Spark Extract")
.enableHiveSupport()
.master("local[*]")
.getOrCreate()
从 hive 中提取表的另一行使用:
val df: DataFrame = spark.sql("SELECT * FROM database.table")
使用 spark.sql("QUERY") 提取表会出现以下异常:
java.lang.RuntimeException: hdfs://localhost:9000/user/hive/warehouse/shopping.db/customers/customers.txt is not a Parquet file. expected magic number at tail [80, 65, 82, 49] but found [46, 48, 48, 10]
at org.apache.parquet.hadoop.ParquetFileReader.readFooter(ParquetFileReader.java:476)
at org.apache.parquet.hadoop.ParquetFileReader.readFooter(ParquetFileReader.java:445)
at org.apache.parquet.hadoop.ParquetFileReader.readFooter(ParquetFileReader.java:401)
at org.apache.spark.sql.execution.datasources.parquet.SpecificParquetRecordReaderBase.initialize(SpecificParquetRecordReaderBase.java:106)
at org.apache.spark.sql.execution.datasources.parquet.VectorizedParquetRecordReader.initialize(VectorizedParquetRecordReader.java:133)
at org.apache.spark.sql.execution.datasources.parquet.ParquetFileFormat$$anonfun$buildReaderWithPartitionValues$1.apply(ParquetFileFormat.scala:404)
at org.apache.spark.sql.execution.datasources.parquet.ParquetFileFormat$$anonfun$buildReaderWithPartitionValues$1.apply(ParquetFileFormat.scala:345)
at org.apache.spark.sql.execution.datasources.FileScanRDD$$anon$1.org$apache$spark$sql$execution$datasources$FileScanRDD$$anon$$readCurrentFile(FileScanRDD.scala:128)
at org.apache.spark.sql.execution.datasources.FileScanRDD$$anon$1.nextIterator(FileScanRDD.scala:182)
at org.apache.spark.sql.execution.datasources.FileScanRDD$$anon$1.hasNext(FileScanRDD.scala:109)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIteratorForCodegenStage1.scan_nextBatch_0$(Unknown Source)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIteratorForCodegenStage1.processNext(Unknown Source)
at org.apache.spark.sql.execution.BufferedRowIterator.hasNext(BufferedRowIterator.java:43)
at org.apache.spark.sql.execution.WholeStageCodegenExec$$anonfun$10$$anon$1.hasNext(WholeStageCodegenExec.scala:614)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:253)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:247)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$25.apply(RDD.scala:836)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$25.apply(RDD.scala:836)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:49)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:324)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:288)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:49)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:324)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:288)
at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:87)
at org.apache.spark.scheduler.Task.run(Task.scala:109)
at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:345)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
at java.lang.Thread.run(Thread.java:748)
我什至尝试了各种方法:
hive> alter table customers SET FILEFORMAT PARQUET;
请协助
解决方案
我什至尝试了各种方法:
hive> alter table customers SET FILEFORMAT PARQUET;
customers.txt
如果文件不是镶木地板,则需要从表格中删除该文件,或者您需要重新定义表格以具有文本文件格式
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