c++ - C++ 中五子棋游戏的计算机播放器
问题描述
前段时间我用 C++ 制作了一个类似于五子棋的游戏，需要两个玩家参与。
现在我想让它成为 Player vs Computer。我试图以最简单的方式做到这一点，通过使计算机的功能来选择一个随机单元格，但我仍然没有成功。我知道为了得到一个随机数，我可以使用 rand() 和这样的字母：
char letters[] = "abcdefghijklmnopqrstuvwxyz";
char x = letters[rand() % 26];
有人可以帮助我并描述如何实现计算机播放器吗？到目前为止，这是我的实现：
#include <iostream>
#include <iomanip>
using namespace std;
void print_table(int x[][15]) {
system("cls");
for (int i = 0; i < 15; i++) {//the loop that use to print out the english character row
if (i == 0)
cout << setw(4) << "A";
else if (i == 1)
cout << " B";
else if (i == 2)
cout << " C";
else if (i == 3)
cout << " D";
else if (i == 4)
cout << " E";
else if (i == 5)
cout << " F";
else if (i == 6)
cout << " G";
else if (i == 7)
cout << " H";
else if (i == 8)
cout << " I";
else if (i == 9)
cout << " J";
else if (i == 10)
cout << " K";
else if (i == 11)
cout << " L";
else if (i == 12)
cout << " M";
else if (i == 13)
cout << " N";
else if (i == 14)
cout << " O";
else if (i == 15)
cout << " P";
}
cout << endl;
for (int i = 0; i < 15; i++) {
cout << setw(2) << i;//print out the row number
for (int j = 0; j < 15; j++) {//print out the board game.
if (x[i][j] == 0) {//the inital value is 0, so when the block is 0 then print out the '.'
cout << " .";
}
else if (x[i][j] == 1) {//when the player O input the block then the value will adding one then if check the block is one then output the 'o'
cout << " O";
}
else if (x[i][j] == 2) {//when the player X input the block then the value will adding two then if check the block is two then output the 'x'
cout << " X";
}
}
cout << endl;
}
}
int check_player(int p) {
if (p == 1) {//change the player everytime before the next loop compile
p++;
}
else {
p--;
}
return p;
}
void input_value(int &t, int &n, int p, int x[][15]) {
char eng;
int number;
do {//the loop that ask for the user input the location.
cout << "player ";
if (p == 1) {
cout << "O";
}
else {
cout << "X";
}
cout << ", make a move: ";
cin >> eng;//input the location
cin >> number;
if (eng == 'A')//change the character to different number
t = 0;
else if (eng == 'B')
t = 1;
else if (eng == 'C')
t = 2;
else if (eng == 'D')
t = 3;
else if (eng == 'E')
t = 4;
else if (eng == 'F')
t = 5;
else if (eng == 'G')
t = 6;
else if (eng == 'H')
t = 7;
else if (eng == 'I')
t = 8;
else if (eng == 'J')
t = 9;
else if (eng == 'K')
t = 10;
else if (eng == 'L')
t = 11;
else if (eng == 'M')
t = 12;
else if (eng == 'N')
t = 13;
else if (eng == 'O')
t = 14;
if (!(eng >= 'A'&&eng <= 'M') || !(number >= 0 && number <= 14) || x[number][t] != 0) {//when the input wrong, output the statement to ask anouther input and loop again.
cout << "Invaid input, Try again!" << endl;
continue;
}
else {//if no problem then this input loop is break and jump to the next statement
break;
}
} while (1);//Because it will break as well so the do-while loop is no any requirement
n = number;
}
int main() {
const int num = 15;//the number for constant the array row and column value
char check_e;//for the user input the column
int R[num][num] = { 0 }, check_n, player = 1, buger = 0, transfer, playerO_win = 0, playerX_win = 0, draw = 0, check_draw;//the variable that for user input or checking the game statment
do {//launch the loop for the user input again and again
check_draw = 0;//reset the checking of draw
print_table(R);
input_value(transfer, check_n, player, R);
R[check_n][transfer] += player;//change the value according the player's input and the player name.
for (int i = 0; i < num; i++) {
for (int j = 0; j < num; j++) {
if (i <= 8 && R[j][i] != 0 && (R[j][i] == R[j][i + 1] && R[j][i] == R[j][i + +2] && R[j][i] == R[j][i + 3] && R[j][i] == R[j][i + 4])) {//the checking for the row bingo
if (R[j][i] == 1) {
playerO_win++;
break;
}
else {
playerX_win++;
break;
}
}
else if (j <= 8 && R[j][i] != 0 && (R[j][i] == R[j + 1][i] && R[j][i] == R[j + 2][i] && R[j][i] == R[j + 3][i] && R[j][i] == R[j + 4][i])) {//the checking for the column bingo
if (R[j][i] == 1) {
playerO_win++;
break;
}
else {
playerX_win++;
break;
}
}
else if (j <= 8 && i <= 8 && R[j][i] != 0 && (R[j][i] == R[j + 1][i + 1] && R[j][i] == R[j + 2][i + 2] && R[j][i] == R[j + 3][i + 3] && R[j][i] == R[j + 4][i + 4])) {//the checking for the \ situation.
if (R[j][i] == 1) {
playerO_win++;
break;
}
else {
playerX_win++;
break;
}
}
else if ((j >= 4 || i >= 4 || i <= 8) && R[j][i] != 0 && (R[j][i] == R[j - 1][i + 1] && R[j][i] == R[j - 2][i + 2] && R[j][i] == R[j - 3][i + 3] && R[j][i] == R[j - 4][i + 4])) {//the checking for the / situation
if (R[j][i] == 1) {
playerO_win++;
break;
}
else {
playerX_win++;
break;
}
}
for (int i = 0; i < num; i++) {//the loop for checking the draw
for (int j = 0; j < num; j++) {//this loop will check for every time compilation.
if (R[j][i] == 0)//when there are any empty block then the check_draw will adding, the draw situation is the check_draw be 0
check_draw++;
}
}
if (check_draw == 0) {//when the check_draw equal to 0 which mean the situation is no empty block
draw++;
break;
}
}
if (playerO_win != 0 || playerX_win != 0 || draw == 1)//break the second loop
break;
}
if (playerO_win == 1 && playerX_win == 0) {// when the player win print the block game again and print out the win statement
print_table(R);
cout << "player O wins!" << endl;
break;
}
else if (playerX_win == 1 && playerO_win == 0) {//the other player win the game
print_table(R);
cout << "player X wins!" << endl;
break;
}
else if (draw == 1) {//the draw block game print
print_table(R);
cout << "Draw game!" << endl;
break;
}
player = check_player(player);
} while (1);//in fact it is no need for the loop statement, because most of the situation will have a break statement for out of the loop
return 0;
}
解决方案
以下是我可能会根据您的初始实现来实现它的方式：
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
#define SIZE 10
#define LINE_LENGTH 4
#define COMPUTER_O_PLAYER true
#define COMPUTER_X_PLAYER false
void print_board(unsigned char x[SIZE][SIZE]) {
cout << " ";
for (int i = 0; i < SIZE; i++) { // The loop that use to print out the english character row.
cout << (char) ('A' + i) << " ";
}
cout << endl;
for (int i = 0; i < SIZE; i++) {
cout << setw(2) << i; // Print out the row number.
for (int j = 0; j < SIZE; j++) {//print out the board game.
if (x[i][j] == 0) { // Unoccupied tile.
cout << " .";
} else if (x[i][j] == 1) { // The tile belongs to X.
cout << " X";
} else { // The tile belongs to O.
cout << " O";
}
}
cout << endl;
}
}
void get_position(int &x, int &y, bool player, unsigned char board[SIZE][SIZE]) {
char eng;
// The loop that ask for the user input the location.
do {
cout << "Player " << (player ? "X" : "O") << ", make a move: ";
cin >> eng;
y = toupper(eng) - 'A';
cin >> x;
if (!(x >= 0 && x < SIZE) || !(y >= 0 && y < SIZE) || board[x][y] != 0) {
// When the input wrong, output the statement to ask another input and loop again.
cout << "Invalid input, Try again!" << endl;
continue;
} else { // If no problem then this input loop is break and jump to the next statement.
break;
}
} while (true);
}
void get_random_position(int &x, int &y, bool player, unsigned char board[SIZE][SIZE]) {
do {
x = rand() % SIZE;
y = rand() % SIZE;
} while ((!(x >= 0 && x < SIZE) || !(y >= 0 && y < SIZE) || board[x][y] != 0));
cout << "Player " << (player ? "X" : "O") << " chose: " << (char) ('A' + y) << x << endl;
}
unsigned int
count_in_direction(unsigned char board[SIZE][SIZE], unsigned int x, unsigned int y, short int m_x, short int m_y) {
unsigned int count = 0;
unsigned char tile = board[x][y];
while (((x + m_x >= 0) && (x + m_x < SIZE)) && ((y + m_y >= 0) && (y + m_y < SIZE)) &&
(board[x + m_x][y + m_y] == tile)) {
x += m_x;
y += m_y;
count++;
}
return count;
}
bool full_line(unsigned char board[SIZE][SIZE], unsigned int x, unsigned int y) {
const short int directions[4][2] = {{1, 0},
{1, -1},
{0, 1},
{1, 1}};
for (const auto &direction : directions) {
if (LINE_LENGTH - 1 <= (count_in_direction(board, x, y, direction[0], direction[1]) +
count_in_direction(board, x, y, -direction[0], -direction[1])))
return true;
}
return false;
}
int main() {
// The variable that for user input or checking the game state.
unsigned char board[SIZE][SIZE] = {0};
int x, y;
bool player = true;
bool draw;
srand(time(nullptr));
// Run the game.
do {
print_board(board);
if ((player && COMPUTER_X_PLAYER) || (!player && COMPUTER_O_PLAYER)) {
get_random_position(x, y, player, board);
} else {
get_position(x, y, player, board);
}
board[x][y] = player ? 1 : 2;
if (full_line(board, x, y)) {
print_board(board);
cout << "player " << (player ? "X" : "O") << " wins!" << endl;
break;
}
draw = true;
for (int k = 0; (k < SIZE) && draw; k++) {
for (int l = 0; (l < SIZE) && draw; l++) {
if (board[k][l] == 0) draw = false;
}
}
if (draw) {
print_board(board);
cout << "Draw game!" << endl;
break;
}
player = !player;
} while (true);
return 0;
}
请深入了解此实现并内化其方法，它还支持作为用户、用户和计算机的玩家，以及同时作为计算机的玩家。
一些见解：
if ... else当有更简单的方法时，不要使用 long 。- 对变量使用正确的数据类型。
- 使用指示性变量命名。
- 尽可能使用循环，不要 long
if ... else。 - 保持代码格式正确。
- 用于
#define定义要使用的全局常量，以便以后更容易更改和可读性。 - 您确实可以使用
rand，但您不需要获取字符，您可以立即获取索引并避免转换。
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