首页 > 解决方案 > Dply 和 RGL:替换 sapply

问题描述

也许是我在这里读到的内容激发了一个奇怪的问题

如何在rgl中增加spheres3d的平滑度

在下面的示例中,有人知道如何使用纯 dplyr 方法而不是 sapply 吗?原因很简单,我倾向于在我的工作流程中尽可能多地使用 dplyr。任何建议表示赞赏。

library(tidyverse)
library(rgl)



sphere1.f <- function(x0 = 0, y0 = 0, z0 = 0, r = 1, n = 101, ...){
  f <- function(s,t){ 
    cbind(   r * cos(t)*cos(s) + x0,
             r *        sin(s) + y0,
             r * sin(t)*cos(s) + z0)
  }
  persp3d(f, slim = c(-pi/2,pi/2), tlim = c(0, 2*pi), n = n, add = T, ...)
}



spheres = data.frame(x = c(1,2,3), y = c(1,3,1), z=c(0,0,0) )
open3d() 
#> Warning in par3d(userMatrix = structure(c(1, 0, 0, 0, 0, 0.342020143325668, :
#> font family "sans" not found, using "bitmap"
#> glX 
#>   1
material3d(ambient = "black", specular = "grey60", emission = "black", shininess = 30.0)
rgl.clear(type = "lights")
rgl.light(theta = -30, phi = 60, viewpoint.rel = TRUE, ambient = "#FFFFFF", diffuse = "#FFFFFF", specular = "#FFFFFF", x = NULL, y = NULL, z = NULL)
rgl.light(theta = -0, phi = 0, viewpoint.rel = TRUE,  diffuse = "gray20", specular = "gray25", ambient = "gray80", x = NULL, y = NULL, z = NULL)

sapply(1:NROW(spheres), function(i) 
  sphere1.f( spheres$x[i], spheres$y[i], spheres$z[i], r=0.5, col = "pink")    )
#> surface surface surface 
#>      14      15      16

reprex 包(v0.3.0)于 2020-12-14 创建

标签: rdplyrrgl

解决方案


这里有几个dplyr/tidyverse方法:

使用pmap_dbl

library(dplyr)
library(purrr)

spheres %>%
  mutate(spheres = pmap_dbl(., ~sphere1.f(..1, ..2, ..3)))

或与rowwise

spheres %>%
  rowwise() %>%
  mutate(spheres = sphere1.f(x, y, z))

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