r - 在 r 中使用强制转换函数时选择了未定义的列
问题描述
我的数据框包含两列:
V1 V2
1 Austria 9.920692e-01
2 Austria 2.037756e+02
3 Austria -2.187730e+02
4 Belgium 7.590994e-01
5 Belgium 8.890127e+01
6 Belgium -1.796152e+02
7 Bulgaria 0.000000e+00
8 Bulgaria 0.000000e+00
9 Bulgaria 0.000000e+00
10 Croatia 3.763559e-01
11 Croatia -4.706601e+00
12 Croatia -3.878768e+02
13 Cyprus 0.000000e+00
14 Cyprus 0.000000e+00
15 Cyprus 0.000000e+00
16 Czech Republic NaN
17 Czech Republic 0.000000e+00
18 Czech Republic NaN
19 Denmark 0.000000e+00
20 Denmark 0.000000e+00
21 Denmark 0.000000e+00
22 Estonia 9.744620e-01
23 Estonia -2.265193e+02
24 Estonia -1.348241e+03
我需要让它变宽。像这样的东西:
Austria 9.920692e-01 2.037756e+02 -2.187730e+02
Belgium 7.590994e-01 8.890127e+01 -1.796152e+02
我尝试使用强制转换功能:
cast(df, V1 ~ V2)
结果我得到:
Using V2 as value column. Use the value argument to cast to override this choice
error `[.data.frame`(data, , variables, drop = FALSE) :
undefined columns selected
我应该如何解决我的问题
解决方案
在基地你可以使用unstack
:
t(unstack(df[2:1]))
# [,1] [,2] [,3]
#Austria 0.9920692 203.775600 -218.7730
#Belgium 0.7590994 88.901270 -179.6152
#Bulgaria 0.0000000 0.000000 0.0000
#Croatia 0.3763559 -4.706601 -387.8768
#Cyprus 0.0000000 0.000000 0.0000
#Czech_Republic NaN 0.000000 NaN
#Denmark 0.0000000 0.000000 0.0000
#Estonia 0.9744620 -226.519300 -1348.2410
数据:
df <- read.table(header=T, text=" V1 V2
1 Austria 9.920692e-01
2 Austria 2.037756e+02
3 Austria -2.187730e+02
4 Belgium 7.590994e-01
5 Belgium 8.890127e+01
6 Belgium -1.796152e+02
7 Bulgaria 0.000000e+00
8 Bulgaria 0.000000e+00
9 Bulgaria 0.000000e+00
10 Croatia 3.763559e-01
11 Croatia -4.706601e+00
12 Croatia -3.878768e+02
13 Cyprus 0.000000e+00
14 Cyprus 0.000000e+00
15 Cyprus 0.000000e+00
16 Czech_Republic NaN
17 Czech_Republic 0.000000e+00
18 Czech_Republic NaN
19 Denmark 0.000000e+00
20 Denmark 0.000000e+00
21 Denmark 0.000000e+00
22 Estonia 9.744620e-01
23 Estonia -2.265193e+02
24 Estonia -1.348241e+03")
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