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python-3.x - 动态更改按钮在 tkinter 中调用的命令的问题

问题描述

在这个简单的计算器 GUI 中，我正在使用类创建一个框架模板。该框架有 2 个标签、2 个输入框和一个按钮。我希望按钮根据function_call初始化时传递的变量运行特定命令 - 但这不起作用。应该为第一个对象调用该two_points函数，并且one_point应该为第二个对象调用该函数。如何根据我正在使用的对象动态更改调用哪个命令？感谢您抽出时间来阅读。

from tkinter import *

root = Tk()
root.title("Simple Slope Calculator")

class Slope_Calc:
    # Variable info that changes within the frame
    def __init__(self, master, num_1, num_2, frame_name, label_1_name, label_2_name, function_call):
        self.num_1 = int(num_1)
        self.num_2 = int(num_2)
        self.frame_name = frame_name
        self.label_1_name = label_1_name
        self.label_2_name = label_2_name
        self.function_call = function_call

        # Frame template
        self.frame_1 = LabelFrame(master, text = self.frame_name, padx = 5, pady = 5)
        self.frame_1.grid(row = self.num_1, column = self.num_2, padx = 10, pady = 10)

        self.label_1 = Label(self.frame_1, text = self.label_1_name)
        self.label_1.grid(row = 0, column = 0)

        self.entry_1 = Entry(self.frame_1)
        self.entry_1.grid(row = 0, column = 1)

        self.label_2 = Label(self.frame_1, text = self.label_2_name)
        self.label_2.grid(row = 1, column = 0)

        self.entry_2 = Entry(self.frame_1)
        self.entry_2.grid(row = 1, column = 1)

        self.calc_button = Button(self.frame_1, text = "Calculate", command = self.function_call) # This is what doesn't work
        self.calc_button.grid(row = 1, column = 2, padx = 5)

    # Strips string of spaces and parentheses
    # Returns a list of relevant ordered pair
    def strip_string(self, entry_num):
        ordered_pair = entry_num.get().split(", ")
        ordered_pair[0] = ordered_pair[0].replace("(", "")
        ordered_pair[1] = ordered_pair[1].replace(")", "")
        return(ordered_pair)

    # Calculates slope based on one point and y-intercept
    def one_point(self):
        pair_1 = self.strip_string(self.entry_1)

        b = int(self.entry_2.get())
        m = (int(pair_1[1]) - b)/(float(pair_1[1]))

        label_3 = Label(self.frame_1, text = "SLOPE-INTERCEPT EQUATION:   y = " + str(m) + "x + " + str(b))
        label_3.grid(row = 2, column = 0, columnspan = 2)


    # Calculates slope based on two points given
    def two_points(self):
        pair_1 = self.strip_string(self.entry_1)
        pair_2 = self.strip_string(self.entry_2)

        m = (int(pair_2[1]) - int(pair_1[1]))/float(int(pair_2[0]) - int(pair_1[0]))
        b = (int(pair_1[1])) - (m*int(pair_1[0]))

        label_3 = Label(self.frame_1, text = "SLOPE-INTERCEPT EQUATION:   y = " + str(m) + "x + " + str(b))
        label_3.grid(row = 2, column = 0, columnspan = 2)
  
# Calling each object
two_p = Slope_Calc(root, 0, 0, "Two Points", "First Ordered Pair", "Second Ordered Pair", "two_points")
one_p = Slope_Calc(root, 0, 1, "One Point and Y-Intercept", "Ordered Pair", "Y-intercept", "one_point")

root.mainloop()

标签： python-3.xtkinterpython-classtkinter-button

解决方案

构造函数的command关键字参数Button应该是一个函数。在这里，你给它一个字符串，它是self应该调用的方法的名称。因此，您必须首先使用此方法setattr才能调用它。这应该这样做：


        def call():
            method = getattr(self, self.function_call)
            method()

        self.calc_button = Button(
            self.frame_1,
            text = "Calculate",
            command = call)

然后你有一个错误，strip_string但那是另一回事。

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