首页 > 解决方案 > SOAP WSS4JInInterceptor 安全处理失败(操作不匹配)

问题描述

我一直在苦苦挣扎,几天来试图获得一个简单的 SOAP 请求以通过 WS-Security,经过许多电子邮件后,我终于能够从服务提供商那里获得一些日志......

请注意,网络服务是 SOAP 1.2

2021-04-11 23:49:24,052:INFO :ajp-nio-127.0.0.1-8009-exec-5:ptor.Soap12FaultOutInterceptor:class org.apache.cxf.binding.soap.interceptor.Soap12FaultOutInterceptor$Soap12FaultOutInterceptorInternalapplication/soap+xml
2021-04-11 23:49:47,867:WARN :ajp-nio-127.0.0.1-8009-exec-28:urity.wss4j.WSS4JInInterceptor:Security processing failed (actions mismatch)
2021-04-11 23:49:47,867:WARN :ajp-nio-127.0.0.1-8009-exec-28:xf.phase.PhaseInterceptorChain:Interceptor for {http://[redacted]/rti/cdd/wsdl}CDDService has thrown exception, unwinding now

可悲的是,这并没有多大帮助,因为在搜索此错误时它似乎很模棱两可,其中一个提到了 WSS4JInInterceptor 中的一个错误,其中正文打开标记和第一个节点之间的空格可能会导致这种情况,但是即使在删除那个空格,我仍然收到同样的错误。

这是我发送的 XML(使用Content-Type: application/soap+xml;charset=utf-8;action="mySoapAction"标头),服务提供商已确认他们正在接收完整的 XML 正文:

<?xml version="1.0"?>
<soapenv:Envelope xmlns:sch="http://[redacted]/rti/cdd/schema" xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope">
    <soapenv:Header>
        <wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis200401-wss-wssecurity-secext-1.0.xsd" soapenv:mustUnderstand="1">
            <wsse:UsernameToken xmlns:wsu="http://docs.oasisopen.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="UsernameToken-1618447264">
                <wsse:Username>[redacted]</wsse:Username>
                <wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-tokenprofile-1.0#PasswordText">[redacted]</wsse:Password>
            </wsse:UsernameToken>
        </wsse:Security>
    </soapenv:Header>
    <soapenv:Body>
        <sch:cddRequest clientID="1213" clientCandidateId="3">
            <candidateName>
                <firstName>Learner</firstName>
                <lastName>Learner</lastName>
            </candidateName>
            <webAccountInfo>
                <email>learner@nowhere.com</email>
            </webAccountInfo>
            <lastUpdate>2021/04/15 00:47:44 BST</lastUpdate>
            <primaryAddress>
                <addressType>Home</addressType>
                <address1>[redacted]</address1>
                <address2>[redacted]</address2>
                <city>Gold Coast</city>
                <postalCode>4218</postalCode>
                <country>AU</country>
                <phone>
                    <phoneNumber>[redacted]</phoneNumber>
                    <phoneCountryCode>[redacted]</phoneCountryCode>
                </phone>
            </primaryAddress>
            <candidatePrefs>
                <candidatePref prefType="ConfirmationPreference">
                    <prefOption>email</prefOption>
                </candidatePref>
                <candidatePref prefType="ReminderPreference">
                    <prefOption>email</prefOption>
                </candidatePref>
                <candidatePref prefType="LocalePreference">
                    <prefOption>en_GB</prefOption>
                </candidatePref>
            </candidatePrefs>
        </sch:cddRequest>
    </soapenv:Body>
</soapenv:Envelope>

非常感谢任何帮助。

标签: soapwss4j

解决方案


您标记了 WSS4J 问题,但您是否有手写安全标头?因为你所有的命名空间都是错误的:

wsse = http://docs.oasis-open.org/wss/2004/01/oasis200401-wss-wssecurity-secext-1.0.xsd
wsu = http://docs.oasisopen.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd
Type attribute = http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-tokenprofile-1.0#PasswordText

注意破折号 ( -)。

正确的命名空间是:

wsse = http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd
wsu = http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd        
Type attribute = http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText

推荐阅读