python - TypeError: 'int' 和 'str' 的实例之间不支持'<'。标记化字符串 100% 整数

Question

Traceback (most recent call last):
  File "Users", line 50, in <module>
    length = len_c / (len_a_b - len_c) 
  File "\venv\lib\site-packages\pandas\core\ops\common.py", line 65, in new_method
    return method(self, other)
  File "\venv\lib\site-packages\pandas\core\arraylike.py", line 97, in __sub__
    return self._arith_method(other, operator.sub)
  File "\venv\lib\site-packages\pandas\core\series.py", line 4994, in _arith_method
    self, other = ops.align_method_SERIES(self, other)
  File "\venv\lib\site-packages\pandas\core\ops\__init__.py", line 147, in align_method_SERIES
    left, right = left.align(right, copy=False)
  File "\lib\site-packages\pandas\core\series.py", line 4220, in align
    return super().align(
  File "\venv\lib\site-packages\pandas\core\generic.py", line 8825, in alig
    return self._align_series(
  File "\venv\lib\site-packages\pandas\core\generic.py", line 8934, in _align_series
    join_index, lidx, ridx = self.index.join(
  File "\venv\lib\site-packages\pandas\core\indexes\range.py", line 690, in join
    return self._int64index.join(other, how, level, return_indexers, sort)
  File "\venv\lib\site-packages\pandas\core\indexes\base.py", line 3669, in join
    return this.join(other, how=how, return_indexers=return_indexers)
  File "\venv\lib\site-packages\pandas\core\indexes\base.py", line 3679, in join
    return self._join_monotonic(
  File "\venv\lib\site-packages\pandas\core\indexe\base.py", line 4014, in _join_monotonic
    join_index, lidx, ridx = self._outer_indexer(sv, ov)
  File "\venv\lib\site-packages\pandas\core\indexes\base.py", line 219, in _outer_indexer
    return libjoin.outer_join_indexer(left, right)
  File "pandas\_libs\join.pyx", line 556, in pandas._libs.join.outer_join_indexer
TypeError: '<' not supported between instances of 'int' and 'str'

Process finished with exit code 1

问题出在以 dict1= 开头的行中

b = df2.apply(set)
a = df1.apply(set)
#print('a', a.columns)
c =  pd.concat([b.apply(lambda x : s.intersection(x)) for s in a], axis=1)
len_a_b = b.apply(lambda x : len(x) +  len(a))
len_c  = c.apply(lambda x : len(x))
dict1 = {'length' : len_c / (len_a_b - len_c) , 'b' : b , 'c' : c}

这是数据框的样子：

0 [Tom, eats, pineapple]
1 [Tom, eats, pineapple]
2 [Eva, eats, apple]
3 [Eva, eats, pineapple]
Name: all, dtype: object
0 [Tom, eats, pineapple]
1 [Tom, eats, pineapple]
2 [Eva, eats, apple]
3 [Eva, eats, pineapple]
Name: sentence, dtype: object

打印（len_c）：长度：550，数据类型：int64

打印（len_a_b）：长度：6646，数据类型：int64

正如您在标记化之后看到的那样，我们在这里有 100% 的整数，但 python 仍然说它没有。当数据不是两个完整的数据帧时，相同的函数可以处理数据。

标签： pythonpandas

Answer 1

而不是这个：

len_c  = c.apply(lambda x : len(x))

用这个：

len_c =c.apply(lambda x : len(x)).reset_index(drop=True)

最后：

dict1 = {'length' : len_c / (len_a_b - len_c) , 'b' : b , 'c' : c}