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python - 在python中解析未格式化的字符串

问题描述

我是python的新手。能够获取以下格式的数据：-

这是代码：-

import paramiko
import json
class Remote_SSH:
    def __init__(self,name,command):
        self.name = name
        self.command = command

    def sshcont(self):
        ssh = paramiko.SSHClient()
        ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
        ssh.connect(hostname = self.name, username='root')
        ssh.invoke_shell()
        stdin, stdout, stderr = ssh.exec_command (self.command)
        cmdout = (stdout.read())
        return cmdout
        ssh.close()

    def ssh_print(self):
        list_logs = []
        ssh = paramiko.SSHClient()
        ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
        ssh.connect(hostname = self.name, username='root')
        sftp = ssh.open_sftp()
        stdin, stdout, stderr = ssh.exec_command (self.command)
        for logs in stdout:
            print logs.strip("\n")
            list_logs.append(logs)
        ssh.close()
        return list_logs

kubectl_pods_data = Remote_SSH('IP_ADDRESS','kubectl get pods --namespace prelude').sshcont()
print '----------------------------------------------------------------'
print kubectl_pods_data
print type(kubectl_pods_data)
print '----------------------------------------------------------------'

这是输出

NAME                                           READY   STATUS    RESTARTS   AGE
abx-service-app-78968c4446-dz586               1/1     Running   0          34d
abx-service-app-78968c4446-mn8jz               1/1     Running   0          34d
abx-service-app-78968c4446-rd8xq               1/1     Running   0          34d
approval-service-5c869c44b6-8vxwd              1/1     Running   0          34d
approval-service-5c869c44b6-j6zgr              1/1     Running   0          34d
approval-service-5c869c44b6-nqxv9              1/1     Running   0          34d

<type 'str'>

如果未运行中的相应值，我想打印名称列中的值。我尝试将其转换为字典，但无法这样做。这里的任何帮助将不胜感激。

标签： pythonlinuxshellkubernetesscripting

解决方案

You can easily convert your string in a list of lists of strings, where every sublist represents a row in your table:

lst_data=[x.split() for x in kubectl_pods_data.split('\n')]

At this point you may transform this structure as you like, or even use it directly: e.g.

for row in lst_data:
    if row[2] != 'Running':
        print(row[0])

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