首页 > 解决方案 > 有人能告诉我为什么这段代码似乎可以工作,但不能……拜托?

问题描述

当我运行这段代码时,我没有收到任何错误,一切似乎都正常,但实际上并没有写入数据库。如果我复制由 print 函数生成的 sql 字符串并将其直接粘贴到 MariaDB 终端会话中,它就可以完美运行。这是生成的sql:

INSERT INTO msg_store (cons, prod, file) VALUES ('XXX','YYY','ZZZ');

如果我更改数据库名称或任何必需的参数,我会按预期得到错误。我已经在其他应用程序中成功使用了大部分代码。我在带有 Python3.7 的 Raspberry Pi 4 上运行它

import pymysql

class C_DataBase: # Database Communication Class
    def __init__(self, host_ip, db_name, user_name, password, poll_time = None):
        self.ip = host_ip
        self.db = db_name
        self.un = user_name
        self.pw = password
        if poll_time is not None:
            self.pt = poll_time

def connect(db):
    try:
        con = pymysql.connect(host=db.ip,  # host
                             user=db.un,  # username
                             passwd=db.pw,  # password
                             db=db.db)  # name of the data base
        return con.cursor()  # Open the database and return

    except Exception as e:
       print('DBOpenError, Failed to Connect to={}, IP={}, user={}, pw={}'.format(db.db, db.ip, db.un, db.pw))

def pub_sql(db, cons, prod, msgb):
    con = connect(db)
    col = "cons, prod, file"
    val ="'" + cons + "','" + prod + "','" +  msgb + "'"

    sql = "INSERT INTO msg_store (" + col + ") VALUES (" + val + ");"
    try:
        rslt = con.execute(sql)
        print(rslt, sql)
        con.close()
    except Exception as e:
        print('SQLWriteError={}'.format(e))


if __name__ == '__main__':
    db = C_DataBase('localhost', 'testdb', 'rpi', 'rpi') # Create and populate a database object
    pub_sql(db, 'XXX', 'YYY', 'AAA') # Call the publishing function

mariaDB 终端会话

;MariaDB [testdb]> INSERT INTO msg_store (cons, prod, file) VALUES ('XXX','YYY','AAA');

Query OK, 1 row affected (33.852 sec)

MariaDB [testdb]>
MariaDB [testdb]> select * from testdb.msg_store;
+------+------+---------+
| cons | prod | file    |
+------+------+---------+
| ABC  | DEF  | message |
| ABC  | DEF  | message |
| XXX  | DEF  | message |
| XXX  | YYY  | ZZZ     |
| XXX  | YYY  | AAA     |
+------+------+---------+
5 rows in set (0.001 sec)

从 Pycharm 运行状态屏幕

标签: python-3.xpymysql

解决方案


之后con.execute()你也应该这样做con.commit()之后你可以关闭连接


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