sql - PostgreSQL 计算子查询中的行数
问题描述
我是 postgresql 的新手,我有下面的查询来产生下一个结果。我想在应用此限制之前计算行数
FROM
(SELECT *
FROM places
LIMIT 10
OFFSET 0) places
SELECT places.place_id,
username,
title,
description,
visible,
score,
placelocation,
category,
price,
accessibility,
places.date,
dangerous,
url,
image_id,
(SELECT COUNT(*) AS likednumber
FROM "favoritePlaces"
WHERE "favoritePlaces".place_id=places.place_id), CASE
WHEN EXISTS
(SELECT *
FROM "favoritePlaces"
WHERE "favoritePlaces".place_id = places.place_id
AND user_id='128'
LIMIT 10) THEN 'true'
ELSE 'false'
END AS liked,
CASE
WHEN EXISTS
(SELECT *
FROM "savedPlaces"
WHERE "savedPlaces".place_id = places.place_id
AND user_id='128'
LIMIT 10) THEN 'true'
ELSE 'false'
END AS saved
FROM
(SELECT *
FROM places
LIMIT 10
OFFSET 0) places
LEFT JOIN images ON images.place_id = places.place_id
WHERE LOWER(description) SIMILAR TO LOWER(Concat('%', '', '%'))
AND LOWER(placelocation) = LOWER(placelocation)
AND category =category
AND price =price
AND dangerous =dangerous
AND accessibility =accessibility
OR LOWER(title) SIMILAR TO LOWER(Concat('%', '', '%'))
AND visible=TRUE
AND placelocation SIMILAR TO placelocation
AND category =category
AND price =price
AND dangerous =dangerous
AND accessibility =accessibility
根据这个答案,我想实现连接语句来计算行数:https ://stackoverflow.com/a/28888696/14131447 ,因为它似乎是更可靠的选择?
我怎么做?
解决方案
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