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java - 如何捕获 2 个元素并合并它们？

问题描述

我希望能够从我的文本文件中捕获每个房间的描述并存储整个描述，而不管它在一个元素中有多少行。

堆栈溢出也不允许我显示我的文本文件实际上是如何格式化的，它实际上是这样的：

编号 = $

房间=

描述：

退出：

但没有空行分隔它们

代码：

package MiniTextBasedGame;

import java.io.File;
import java.io.IOException;
import java.nio.charset.StandardCharsets;
import java.nio.file.Files;
import java.nio.file.Path;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class fileParser {

    public static String[] getLines(File file){
        String contents = null;
        Path path = file.toPath();
        String[] lines = null;
        try {
            contents = Files.readString(path, StandardCharsets.ISO_8859_1);
        } catch (IOException ex) {
            System.out.println("Error");
        }
        lines = contents.split("\n");
        return lines;
    }
    public static void getRoomID(String[] array){
        ArrayList<String> arraylist= new ArrayList<>(Arrays.asList(array));
        ArrayList<String> idarraylist = new ArrayList<>();
        for (String str: arraylist) {
            if(str.contains("ID")){
               String temp = str.substring(5, 6);
               idarraylist.add(temp);
            }
        }
    }
    public static void getRoomName(String[] array){
        ArrayList<String> arraylist= new ArrayList<>(Arrays.asList(array));
        ArrayList<String> namearraylist = new ArrayList<>();
        for (String str: arraylist) {
            if(str.contains("name =")){
                String temp = str.substring(7);
                namearraylist.add(temp);
            }
        }
    }
    public static void getRoomDescription(String[] array){
        ArrayList<String> darray = new ArrayList<>(Arrays.asList(array));
        ArrayList<String> tempArray = new ArrayList<>();
        for (String str: darray) {
            if (!(str.contains("ID") || str.contains("name =") || str.contains("Description:") || str.contains("exits"))) {
                if (!str.isBlank()) {
                    tempArray.add(str);
                }
            }
        }
        // Print out results
        for (String str: tempArray) {
            System.out.println(str);
        }
    }
    public static void getExits(String[] array){

    }
}

文本文件：

ID = 0
name = Beginning 
Description: Y0ou are standing at the end of a road before a dark and dank cave. The forest is 
covering the road lending a dark and spooky aspect to the road. You hear a low wailing that 
seems to be coming from the cave. 
exits : East


ID = 1 
name = Room1 
Description: Y1ou are standing at the end of a
road before a dark and dank cave. The forest is covering the road
lending a dark and spooky aspect to the road. You hear a low wailing
that seems to be coming from the cave. exits : East, West, South

ID = 2 
name = Room2
Description: Y2ou are standing at the end of a
road before a dark and dank cave. The forest is covering the road
lending a dark and spooky aspect to the road. You hear a low wailing
that seems to be coming from the cave. 
exits : South, West

ID = 3
name = Room3 
Description: Y3ou are standing at the end of a
road before a dark and dank cave. The forest is covering the road
lending a dark and spooky aspect to the road. You hear a low wailing
that seems to be coming from the cave. 
exits : North, West

ID = 4
name = Room4 
Description: Y4ou are standing at the end of a
road before a dark and dank cave. The forest is covering the road
lending a dark and spooky aspect to the road. You hear a low wailing
that seems to be coming from the cave. 
exits : East, North, South

ID = 5 
name = End 
Description: Y5ou are standing at the end of a road
before a dark and dank cave. The forest is covering the road lending a
dark and spooky aspect to the road. You hear a low wailing that seems
to be coming from the cave. 
exits : North

标签： java

解决方案

你最好使用正则表达式来解析你的文件。这是一个可以从文件中提取信息的示例正则表达式：

ID = ([0-9]+)\s*name = (.*)\s*Description: ([\s\S]+?)exits : (.*)

https://regexr.com/64un0

在 Java 中使用它：

    String str = Files.readString(path, StandardCharsets.ISO_8859_1);

    Pattern p = Pattern.compile("ID = ([0-9]+)\\s*name = (.*)\\s*Description: ([\\s\\S]+?)exits : (.*)");
    Matcher m = p.matcher(str);
    while(m.find())
    {
        String id = m.group(1).trim();
        String name = m.group(2).trim();
        String description = m.group(3).trim();
        String exits = m.group(4).trim();
        //do the rest...
    }

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