arrays - 基于键值数组重新排序 ruby​​ 中的哈希数组

Question

我有一个哈希数组。例如，

arr =[[{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}],
     [{:id=>65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
     [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}]]

order_arr = [65,69,61]

如何以键的给定顺序（基于'order_arr'）重新排序上述数组：id。

所以，结果应该如下：

[[{:id=> 65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
  [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}],
  [{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}]]

请帮忙

标签： arraysruby-on-railsrubyhash

Answer 1

我使用您的索引对order_arr数组数组进行排序sort_by

arr =[[{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}],
     [{:id=>65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
     [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}]]


order_arr = [65,69,61]
sorted_arr = arr.sort_by { |ary| order_arr.index(ary.first[:id]) }

pp sorted_arr