javascript - 显示嵌套数组的所有 slug
问题描述
我被这个困住了,我不明白为什么。我有一个包含所有帖子数据的数组(json 文件),我想在我的页面上显示一些元素。我成功地显示了简单的元素,但我不知道如何显示嵌套数组的每个元素。我想显示每个帖子的所有 slug 类别。使用我的 const post_category 我只能访问第一个 slug。
所以有我的代码。谢谢 !
[{
"id": 510,
"slug": "red-bull",
"title": "Red Bull™",
"link": "#",
"thumbnail": "#",
"category": [{
"term_id": 7,
"name": "Identité Visuelle",
"slug": "iv",
"term_group": 0,
"term_taxonomy_id": 7,
"taxonomy": "categorie",
"description": "",
"parent": 0,
"count": 25,
"filter": "raw",
"term_order": "1"
}, {
"term_id": 3,
"name": "Signalétique",
"slug": "s",
"term_group": 0,
"term_taxonomy_id": 3,
"taxonomy": "categorie",
"description": "",
"parent": 0,
"count": 7,
"filter": "raw",
"term_order": "5"
}]
}, {
"id": 491,
"slug": "dogzout-records",
"title": "Dogzout Records®",
"link": "#",
"thumbnail": "#",
"category": [{
"term_id": 7,
"name": "Identité Visuelle",
"slug": "iv",
"term_group": 0,
"term_taxonomy_id": 7,
"taxonomy": "categorie",
"description": "",
"parent": 0,
"count": 25,
"filter": "raw",
"term_order": "1"
}, {
"term_id": 6,
"name": "Vidéo Motion",
"slug": "vm",
"term_group": 0,
"term_taxonomy_id": 6,
"taxonomy": "categorie",
"description": "",
"parent": 0,
"count": 19,
"filter": "raw",
"term_order": "2"
}]
}, {
...
}]
$('#project-loader').on('click', function () {
let pull_page = 1;
let jsonFlag = true;
if (jsonFlag) {
jsonFlag = false;
pull_page++;
$.getJSON("/bklt-wp/wp-json/projets/all-projects?page=" + pull_page, function (data) {
if (data.length) {
var items = [];
$.each(data, function (key, val) {
const arr = $.map(val, function (el) { return el });
// const post_url = arr[1];
const post_title = arr[2];
const post_link = arr[3];
const post_thumbnail = arr[4];
const post_category = arr[5].slug;
let item_string = '<li class="project__item"><a href="' + post_link + '" class="project__link" data-project="' + post_category + '">' + post_title + '\xa0' + '<div class="project__italic">(<ul class="category__list italic plus"></ul>)</div><span>,' + '\xa0' + '</span></a><img src="' + post_thumbnail + '" class="project__img"></li>';
items.push(item_string);
});
for (var i = 0; i < data.length; i++) {
if (data[i]["category"].length > 0) {
var outputhtml = "";
outputhtml += "(";
outputhtml += data[i]["category"].map(a => a.slug).join();
outputhtml += ")";
}
$(".category__list .italic .plus").append('<li class="category__item">' + outputhtml + '</li>');
}
if (data.length >= 25) {
$('li.loader').fadeOut();
$(".project__list").append(items);
} else {
$(".project__list").append(items);
$('#project-loader').hide();
$('#ajax-no-posts').fadeIn();
}
} else {
$('#project-loader').hide();
$('#ajax-no-posts').fadeIn();
}
}).done(function (data) {
if (data.length) { jsonFlag = true; }
});
}
});
解决方案
你想要这样的东西。显示父类 slug 和他们的子 slug?我刚刚使用循环进行演示。你会明白的
var x = [
{
id: 510,
slug: "red-bull",
title: "Red Bull™",
link: "#",
thumbnail: "#",
category: [
{
term_id: 7,
name: "Identité Visuelle",
slug: "iv",
term_group: 0,
term_taxonomy_id: 7,
taxonomy: "categorie",
description: "",
parent: 0,
count: 25,
filter: "raw",
term_order: "1",
},
{
term_id: 3,
name: "Signalétique",
slug: "s",
term_group: 0,
term_taxonomy_id: 3,
taxonomy: "categorie",
description: "",
parent: 0,
count: 7,
filter: "raw",
term_order: "5",
},
],
},
{
id: 491,
slug: "dogzout-records",
title: "Dogzout Records®",
link: "#",
thumbnail: "#",
category: [
{
term_id: 7,
name: "Identité Visuelle",
slug: "iv",
term_group: 0,
term_taxonomy_id: 7,
taxonomy: "categorie",
description: "",
parent: 0,
count: 25,
filter: "raw",
term_order: "1",
},
{
term_id: 6,
name: "Vidéo Motion",
slug: "vm",
term_group: 0,
term_taxonomy_id: 6,
taxonomy: "categorie",
description: "",
parent: 0,
count: 19,
filter: "raw",
term_order: "2",
},
],
},
];
//updated ans:
for (var i = 0; i < x.length; i++) {
var outputhtml="";
outputhtml += x[i]["slug"];
if (x[i]["category"].length > 0) {
outputhtml +="(";
outputhtml+=x[i]["category"].map(a => a.slug).join();
outputhtml +=")"
}
console.log(outputhtml);
$(".category__list").append('<li class="category__item">' + outputhtml + '</li>');
}
/* old ans
for (var i = 0; i < x.length; i++) {
console.log("parent slug:", x[i]["slug"]);
if (x[i]["category"].length > 0) {
for (var j = 0; j < x[i]["category"].length; j++) {
console.log("child slug->", x[i]["category"][j]["slug"]);
}
}
}
*/
<script src="//ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<!-- working here. -->
<div class="category__list"></div>
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