r - 更快地制作基于标签对照片进行排序的脚本
问题描述
嗨,我不知道这是否是 SO 的合法问题。但我有一个脚本,用于根据标签将照片分类到文件夹中。它使用exifr
包来执行此操作。
但是,它的运行速度非常慢。我尝试使用指南对其进行改进,但我所做的最终无法正常工作。是否有了解矢量化和/或优化的人可以提出一些建议。谢谢!
#----- Imports ----
library(exifr)
# ---------- Functions ----------
'%!in%' <- function(x,y)!('%in%'(x,y))
tagcatcher <- function(dat){
tags <- c()
for (tagNameTry in keywords_names ) {
if (tagNameTry %in% names(dat)) {
xs <- dat[tagNameTry]
if (typeof(xs) == "list") {
xs <- xs[[1]]
l <- length(xs[[1]])
x <- c()
for (i in 1:l) {
x <- c(x,xs[[1]][i])
}
} else {
x <- xs
}
tags <- c(tags,x)
}
}
tags <- unique(tags)
return(tags)
}
# ----------- Settings ----------
ss <- "/"
haystacks <- c("H:MyPhotos")
organizedMediaPhotos <- "V:/Photos"
all_files <- list.files(haystacks,recursive = TRUE, full.names = TRUE)
keywords_names <- c("Category","XPKeywords","Keywords")
ctags <- list.dirs(organizedMediaPhotos)[list.dirs(organizedMediaPhotos) %!in% organizedMediaPhotos]
current_tags <- c()
for (ctag in ctags) {
x <- strsplit(ctag,"/")
x <- x[[1]]
x <- x[length(x)]
current_tags <- c(current_tags,x)
}
# Main Loop - That Needs to be faster
for (cur_file in all_files) {
print(cur_file)
cur_dat <- read_exif(cur_file,tags=keywords_names)
tags <- tagcatcher(cur_dat)
for (tag in tags) {
tag_folder <- paste(organizedMediaPhotos,ss,tag,sep="")
if (tag %!in% current_tags) {
dir.create(tag_folder)
print(paste("creating tag folder: ",tag_folder))
}
pic_path <- paste(tag_folder,ss,basename(cur_file),sep="")
if (!file.exists(pic_path)) {
file.copy(cur_file,pic_path)
print(paste("moved file from ",cur_file, " to ", pic_path))
}
}
}
解决方案
你可以试试这个
for x in *.jpg; do
d=$(date -r "$x" +%Y-%m-%d)
mkdir -p "$d"
mv -- "$x" "$d/"
done
对于 powershell:
Param(
[string]$source,
[string]$dest,
[string]$format = "yyyy/yyyy_MM/yyyy_MM_dd"
)
$shell = New-Object -ComObject Shell.Application
function Get-File-Date {
[CmdletBinding()]
Param (
$object
)
$dir = $shell.NameSpace( $object.Directory.FullName )
$file = $dir.ParseName( $object.Name )
# First see if we have Date Taken, which is at index 12
$date = Get-Date-Property-Value $dir $file 12
if ($null -eq $date) {
# If we don't have Date Taken, then find the oldest date from all date properties
0..287 | ForEach-Object {
$name = $dir.GetDetailsof($dir.items, $_)
if ( $name -match '(date)|(created)') {
# Only get value if date field because the GetDetailsOf call is expensive
$tmp = Get-Date-Property-Value $dir $file $_
if ( ($null -ne $tmp) -and (($null -eq $date) -or ($tmp -lt $date))) {
$date = $tmp
}
}
}
}
return $date
}
function Get-Date-Property-Value {
[CmdletBinding()]
Param (
$dir,
$file,
$index
)
$value = ($dir.GetDetailsof($file, $index) -replace "`u{200e}") -replace "`u{200f}"
if ($value -and $value -ne '') {
return [DateTime]::ParseExact($value, "g", $null)
}
return $null
}
Get-ChildItem -Attributes !Directory $source -Recurse |
Foreach-Object {
Write-Host "Processing $_"
$date = Get-File-Date $_
if ($date) {
$destinationFolder = Get-Date -Date $date -Format $format
$destinationPath = Join-Path -Path $dest -ChildPath $destinationFolder
# See if the destination file exists and rename until we get a unique name
$newFullName = Join-Path -Path $destinationPath -ChildPath $_.Name
if ($_.FullName -eq $newFullName) {
Write-Host "Skipping: Source file and destination files are at the same location. $_"
return
}
$newNameIndex = 1
$newName = $_.Name
while (Test-Path -Path $newFullName) {
$newName = ($_.BaseName + "_$newNameIndex" + $_.Extension)
$newFullName = Join-Path -Path $destinationPath -ChildPath $newName
$newNameIndex += 1
}
# If we have a new name, then we need to rename in current location before moving it.
if ($newNameIndex -gt 1) {
Rename-Item -Path $_.FullName -NewName $newName
}
Write-Host "Moving $_ to $newFullName"
# Create the destination directory if it doesn't exist
if (!(Test-Path $destinationPath)) {
New-Item -ItemType Directory -Force -Path $destinationPath
}
robocopy $_.DirectoryName $destinationPath $newName /mo
PS:几年前我尝试过这个,它就像一个魅力
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