python - 如何在 Matplotlib 中绘制单个轮廓线

Question

以下代码是从这里借用的：

import numpy as np
import matplotlib.cm as cm
import matplotlib.pyplot as plt


delta = 0.025
x = np.arange(-3.0, 3.0, delta)
y = np.arange(-2.0, 2.0, delta)
X, Y = np.meshgrid(x, y)
Z1 = np.exp(-X**2 - Y**2)
Z2 = np.exp(-(X - 1)**2 - (Y - 1)**2)
Z = (Z1 - Z2) * 2

fig, ax = plt.subplots()
CS = ax.contour(X, Y, Z)
ax.clabel(CS, inline=True, fontsize=10)
ax.set_title('Simplest default with labels')

上面的代码生成具有 7 条等高线的等高线图。如何用值绘制一条轮廓线0.5？

上述代码的输出是：

标签： pythonmatplotlib

Answer 1

只需添加轮廓值： CS = ax.contour(X, Y, Z, [0.5])

import numpy as np
import matplotlib.cm as cm
import matplotlib.pyplot as plt


delta = 0.025
x = np.arange(-3.0, 3.0, delta)
y = np.arange(-2.0, 2.0, delta)
X, Y = np.meshgrid(x, y)
Z1 = np.exp(-X**2 - Y**2)
Z2 = np.exp(-(X - 1)**2 - (Y - 1)**2)
Z = (Z1 - Z2) * 2

fig, ax = plt.subplots()
CS = ax.contour(X, Y, Z, [0.5])
ax.clabel(CS, inline=True, fontsize=10)
ax.set_title('Simplest default with labels')

plt.show()